Proving The Sum Of The Interior Angle Measures Of A Triangle Is 180 (2024)

Answer: X-axis

Step-by-step explanation: The arrow is pointing to the horizontal line on the on the graph. That horizontal line is the x-axis.

Answer: sqrt(182)

Step-by-step explanation:

Answer:

y = -3x + 5

Step-by-step explanation:

y = mx + c

gradient = -3 = m

y-intercept = 5 = c

The height of the cone with a volume of 1/18π ft³ is: 1.5 ft.

What is the Volume of a Cone?

Volume of a cone = 1/3πr²h, where, h = height of cone, and r = radius of the cone.

Given the following:

Volume = 1/18 π ft³Diameter = 2/3 ftRadius = (2/3)/2 = 1/3 ftHeight (h) = ?

Plug in the values into the volume formula:

1/18π = 1/3π(1/3)²h

1/18π = 1/3π(1/9)h

1/18π = (πh)/27

Divide both sides by π

1/18 = h/27

Cross multiply

27 = 18h

27/18 = h

h = 1.5

Therefore, the height of the cone with a volume of 1/18π ft³ is: 1.5 ft.

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The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).

The given expression is: [tex]2x^{2} +3x-54[/tex]

What is a factor?

A factor is a number that divides another number leaving no remainder.

We can rewrite the given expression as:

[tex]2x^{2} +12x-9x-54[/tex] (middle term has been splitted)

Take 2 as common from first two terms while take -9 as common from last two terms.

[tex]2x(x+6)-9(x+6)[/tex]

Take (x+6) as common

[tex](x+6) (2x-9)[/tex]

So, we got the factors (x+6) and (2x-9)

Therefore, The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).

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The area of the shaded region is [tex]\rm (150\sqrt{3} \ - 75\pi ) \ feet^2[/tex] option first is correct.

It is given that a circle is inscribed in a regular hexagon with sides of 10 feet.

It is required to find the shaded area (missing data is attached shown in the picture).

What is a circle?

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have a hexagon with a side length of 10 feet.

We know the area of the hexagon is given by:

[tex]\rm A = \frac{3\sqrt{3} }{2} a^2[/tex] where a is the side length.

[tex]\rm A = \frac{3\sqrt{3} }{2} 10^2[/tex] ⇒ [tex]150\sqrt{3}[/tex] [tex]\rm feet^2[/tex]

We have the shortest length = x feet and from the figure:

2x = 10

x = 5 feet

The radius of the circle r = longer leg

[tex]\rm r = x\sqrt{3} \Rightarrow 5\sqrt{3}[/tex] feet

The area of the circle a = [tex]\pi r^2[/tex] ⇒ [tex]\pi (5\sqrt{3} )^2 \Rightarrow 75\pi \ \rm feet^2[/tex]

The area of the shaded region = A - a

[tex]\rm =(150\sqrt{3} \ - 75\pi ) \ feet^2[/tex]

Thus, the area of the shaded region is [tex]\rm (150\sqrt{3} \ - 75\pi ) \ feet^2[/tex]

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Answer:

option A

Step-by-step explanation:

Step-by-step explanation:

3 blue

4 red

2 yellow

in total 9 marbles.

when looking at the 3 blue marbles that leaves 9-3 = 6 others (red and yellow).

so, the ratio is

3:6 = 1:2

remember, a ratio is a fraction and follows the same rules of calculation, simplification, ...

The expressions BC and AB are illustrations of straight lines

The length AC is 25 units

How to determine the length of AC?

The given parameters are:

BC =7

AB = 16

Assume that AB and BC are straight lines.

Then , we have:

AC =AB + BC

Substitute known values

AC = 16 + 7

Evaluate the sum

AC = 25

Hence, the length AC is 25 units

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Answer:

72%

Step-by-step explanation:

We have 10 sudents in class 1 and 40 in the other for a total of 50 students.

The 10 in class 1 had a mean of 80 so we do 80x10=800

The mean of the class of 40 is 70, so we do 40x70=2800

we add both of those together to get 3600 then we divide that by 50 because there are 50 students in total.

3600/50=72.

Answer:

12.39cm

Step-by-step explanation:

cos 25°=AB/12.5

AB=12.5 cos 25°

cos 25°=0.9912

AB=12.5×0.9912

=12.39cm

Answer: = 2(7 + 3) ^2= 2 * 10^2= 200

Answer: number 2

Step-by-step explanation: so a supplementary Angle adds up to a 180 angle so it would be number 2 I think.

Answer:

x= 7/2

Step-by-step explanation:

move the constant 2x+5=12 to make it 2x=12-5.

subtract 12-5= 7

2x=7 divide both sides

x=7/2

i did try my best hope this helps :)

The diameter of a sphere with a volume of 397 meter cube to the nearest tenth of a meter is 9.1 meters

Volume of a sphere

volume of a sphere = 4 / 3 πr³

where

r = radius of the sphere

Therefore,

volume = 397m³

Diameter = radius × 2

Hence,

volume of a sphere = 4 / 3 πr³

volume of a sphere = 4 / 3 × 3.14 × r³

397 = 12.56 / 3 r³

cross multiply

397 × 3 = 12.56 r³

1191 = 12.56 r³

divide both sides by 12.56

r³ = 1191 / 12.56

r = ∛94.8248407643

r = 4.56009658

Hence,

diameter = 4.56009658 × 2 = 9.12 = 9.1 meters

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ANSWER

it is the one that is highlighted Yellow

f=±✓de/4e

photo is how you do the work

The measure of the missing angle(a) in the isosceles triangle(two sides and angle equal) is 70 degrees.

What is an Isosceles triangle?

An Isosceles triangle is a triangle that has two of it sides equal to each other and two of it angles equal to each other.

The base angle of an isosceles triangle are equal. Therefore, let's find angle a in the triangle.

55 + 55 + a = 180

Recall the sum of angle in a triangle is 180 degrees.

110 + a = 180

subtract 110 from both sides

110 - 110 + a = 180 - 110

a = 70 degrees

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Answer:

7/8

Step-by-step explanation:

First you have to make the fractions into a common denominator. So I made 1 1/4 into 10/8. Now you just subtract 2/8 from 10/8 and get 7/8.

Given is an A.P. in which -

First term,a = 2Common difference = Second term - First term

[tex]\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = a_2-a_1[/tex]

[tex]\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = 7-2 [/tex]

[tex]\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = 5[/tex]

Solution:-

nth term of an A.P ,is given by-

[tex]\green{ \underline { \boxed{ \sf{a_n =a+(n-1)d }}}}[/tex]

where

[tex]a_n = nth \;term[/tex]a = first termn = number of termd = common difference

Putting n = 46

[tex]\begin{gathered}\\\implies \sf a_{46}= 2 + (46-1)\times 5 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies \sf a_{46}= 2 + 45\times 5 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies \sf a_{46}= 2 + 225 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies \sf a_{46}= 227 \\\end{gathered} [/tex]

[tex]\longrightarrow[/tex]Therefore, the 46th term is 227

Hence, the [tex]46th[/tex] term is [tex]227[/tex].

What is the sequence?

A sequence is a list of objects, typically numbers, in which order matters, repetition is allowed, and the same elements can appear multiple times at different positions in the sequence.

Here given sequence is

[tex]2,7, 12,...[/tex]

Here,

[tex]a=2[/tex]

[tex]d=a_2-a_1\\d=7-2\\d=5[/tex]

The general formula of the sequence is

[tex]a_n=a+(n-1)d[/tex]

where,

[tex]a_n=[/tex] nth term

[tex]a[/tex] is the first term

[tex]d[/tex] is the common difference

[tex]n[/tex] is the number of terms

Now substituting the values in general formula is

[tex]a_{46}=2+(46-1)5\\\\a_{46}=2+(45)5\\\\a_{46}=2+225\\\\a_{46}=227\\[/tex]

Hence, the [tex]46th[/tex] term is [tex]227[/tex].

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#SPJ2

Answer:

Step-by-step explanation:

Answer:

B=5

Step-by-step explanation:

If 7 plus a equals 9 then a would equal 2.

2+8=b+5

10=b+5

Ask yourself what number plus 5 equals 10

B is 5 because 5 plus 5 is 10

Answer:

2 v 13, 2 Square root 13

Step-by-step explanation:

there's 2 right triangles

a)

10^2 = 6^ + a^2

100 - 36 = a^2

64 = a ^2

a = 8

--------------------------------------------

now we know the base of the right triangle = 8

and also the base of the left one = 4

8 + 4 = 12

--------------------------------------------

now find x

b)

x^2 = 6^2 + 4^2

x^2 = 36 + 16

x^2 = 52

x = (square root) 52

x = 2 v 13 <---- "v = square root"

Question :- Find the unknown side .

Instructions :- Simplify the answer if there is square root

Given :- Two triangles Total length of the base 12 First triangle dimensions10 as it's hypotenuse6 as it's perpendicular

Answer:- X = ✓ 52 = 7.2

Explanation:-

Formula :-

hypotenuse² = perpendicular²+base²

Solution:-

First triangle:-

[tex] {h}^{2} = {p}^{2} + {b}^{2} \\ {10}^{2} = {6}^{2} + {b}^{2} \\ 100 = 36 + {b}^{2} \\ 100 - 36 = {b}^{2} \\ 64 = {b}^{2} \\ 8 = b[/tex]

Second triangle

perpendicular = 6 hypotenuse = X ( to Find )base = 12-b = 12-8= 4

[tex] {h}^{2} = {p}^{2} + {b}^{2} \\ {x}^{2} = {6}^{2} + {4}^{2} \\ {x}^{2} = 36 + 16 \\ {x}^{2} = 52 \\ x = \sqrt{52} = 7.2 \\ x = 7 \: \: approx[/tex]

Answer: Between 1 and 3.

Step-by-step explanation:

You have to Think about y too, y can be anything, but let's say y is 1. Then x should be 3

x = 4, y = 6

In this case, you can solve the equation by substitution.

3x + 4y = 36

We are given that y = -1/2x + 8

Plug in that value assigned to y.

3x + 4(-1/2x + 8) = 36

3x -2x + 32 = 36

x + 32 = 36

x = 4

Now, we can return back to y

y = -1/2x + 8

y = -1/2(4) + 8

y = -2 + 8

y = 6

The required equation f(10) = 13.52 mg remains.

We have given that ,

m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60

What is the fromula for he amount of a radioactive substance remaining after t years?

The amount of a radioactive substance remaining after t years is given by the function

[tex]f(t)=m(0.5)^{t/h}[/tex]............ (1),

where m = initial mass and h= half-life in years.

Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,

then from equation (1) we get,

[tex]f(10)=50(0.5)^{10/5.3}[/tex]

Therefore the required equation f(10) = 13.52 mg .

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Answer:

The required equation f(10) = 13.52 mg remains.

We have given that ,

m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60

What is the fromula for he amount of a radioactive substance remaining after t years?

The amount of a radioactive substance remaining after t years is given by the function

............ (1),

where m = initial mass and h= half-life in years.

Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,

then from equation (1) we get,

Therefore the required equation f(10) = 13.52 mg .

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Answer:

12.16 inches.

Step-by-step explanation:

Use pythagoras thereom since they are right angle triangles. A² = c² - b².

For NP triangle:

10² - 4² = 84. square root of 84 is 9.165.

For MN triangle:

5² - 4² = 9. square root of 9 is 3.

finally, add them up:

3 + 9.165 = 12.165, to 2 d.p., it is 12.16 inches.

Answer:

21.75

Step-by-step explanation:

Because 6.00+6.25=12.25+7.00=19.75+8.00=27.75

Answer:

x=0

Step-by-step explanation:

because you divide by x^12

x^n=x^0

x=0

Answer:

1440 ounces

Step-by-step explanation:

there are 16 ounces in a pound so multiply 90 by 16 and you get 1440 hope this helps!

Answer:

She will pay $40 more.

Step-by-step explanation:

I used the equation y=27.50x + 25 to find this out and made x = 12 to represent how many months she is paying.

now putting x into the equation, y = 27.50(12) + 25

First i did the multiplication, 27.50 x 12 = $330.

Then I added 25 to 330 for the down payment, 330 + 25 = 355

I then did 355 - 315 to find out how much more you would pay,

355 - 315 = $40

Hope this helps!

Step-by-step explanation:

so, the scale is 1/4 cm to 1 m.

1 m = 100 cm.

1 m² = 100×100 = 10,000 cm²

that means the scaling factor is 0.25/100 = 1/400

(after multiplying with 4/4).

so, every length in reality has to be multiplied by 1/400 to get the length on the plan.

the area of a rectangle is

length × width.

now, applying the scaling factor means that

length×1/400 × width×1/400 = 40

length × width × 1/400×1/400 = actual area × 1/400² = 40

actual area = 40×400² = 6,400,000 cm²

= 6,400,000 / 10,000 = 640 m²